Explicit member function template specialisation on Visual Studio 2019

Template member function templates

  Classes can have member function templates. These member templates can be explicit specialized. For example:

struct Foo
{
   template <typename T>
   void f()
   {
   }
};

template <>
inline void Foo::f<int>()
{
   // full specialization
}

It seems that Visual Studio 2019 allows for an illegal syntax with the full specialization declaration in the class itself:

struct Foo
{
   template <typename T>
   void f();
   
   // illegal?
   template <>
   void Foo::f<int>();
};

template <>
void Foo::f<int>()
{
}

Also the inline specifier isn't necessary then in Visual Studio without running into errors with duplicate symbols.

Links

• Explicit specialization of member function template in source file